| Cemalizim | 19 Temmuz 2008 15:34 |
Matrisi Eşelon Forma Çevirir
PHP- Kodu:
#include <stdio.h>
int verigirisi(int m, int n);
int main()
{/*mian*/
int m,n,devammi;
printf("matrisin boyutlarini giriniz:\n");
scanf("%d%3d",&m,&n);
verigirisi(m,n);
printf("-----------yeni bir matris girmek icin 1 'e\n\n\n-----------programdan cikmak icin 0 'a basiniz.\n\n");
scanf("%d",&devammi);
if((devammi!=0)&&(devammi!=1)){/*if*/
printf("yanlis tercih yaptiniz..\n\ntekrar giriniz..\n");
scanf("%d",&devammi);
}/*endof if*/
switch(devammi){/*switch*/
case 1:
main();
case 0:
break;
}/*switch'in sonu*/
}/*endof main*/
int verigirisi(int a, int b)
{
float Array[a][b],temp1[b],temp2[b];
float bolucu,k;
int y,i,j,z,t,e,ti,tj;
int kontrol;
for(i=0; i<a; i++)
for(j=0; j<b; j++)
Array[i][j]=0;
printf("verileri giriniz:\n\n");
printf("verilerin girisini satir satir sirayla yapiniz..\n");
for(i=0; i<a; i++)
for(j=0; j<b; j++){
scanf("%f",&Array[i][j]);}
printf("Girdiginiz Matris;\n");
for(i=0; i<a; i++)
for(j=0; j<b; j++){
printf("%f\t",Array[i][j]);
if(j==(b-1)){
printf("\n");}
}
printf("\n\n\n");
for(ti=0; ti<a; ti++)
for(tj=0; tj<b; tj++){//for1
i=ti;
j=tj;
t=j;
z=i;
if(i==j){//if1
bolucu=Array[i][i];
if(bolucu==0)
{
for(j=0; j<b; j++){/*for1*/
temp1[j]=Array[i][j];}/*for1end*/
for(i=(a-1); i>t; i--){/*for2*/
if(Array[i][t]!=0){/*if3*/
for(j=0; j<b; j++)
temp2[j]=Array[i][j];
break;
}/*if3end*/
}/*for2end*/
for(j=0; j<b; j++){/*for3*/
Array[z][j]=temp2[j];
Array[i][j]=temp1[j];
}/*for3end*/
printf("Yerdegistirme iterasyonu;\n");
for(i=0; i<a; i++)
for(j=0; j<b; j++){//for
printf("%f\t",Array[i][j]);
if(j==(b-1)){//if
printf("\n");}//ifend
}//forend
printf("\n\n\n");
bolucu=Array[z][z];
for(j=0; j<b; j++){//for2
Array[z][j]=(Array[z][j]/bolucu);
if(j==(b-1)){//if2
printf("\n");}//if2end
}//for2end
for(y=0; y<(a-1); y++){//for3
if(y>=t){//if3
e=t;
k=Array[(y+1)][e];
for(e=0; e<b; e++){//for4
Array[(y+1)][e]=(-1)*k*Array[z][e]+Array[(y+1)][e];
}}//for3-4end
printf("\n");
}//if3end
printf("Iterasyon sonucu;\n");
for(i=0; i<a; i++)
for(j=0; j<b; j++){
printf("%f\t",Array[i][j]);
if(j==(b-1)){
printf("\n");}
}
printf("\n\n\n");
}//ifbolucuend
else
{
for(j=0; j<b; j++){//for2
Array[i][j]=(Array[i][j]/bolucu);
if(j==(b-1)){//if2
printf("\n");}//if2end
}//for2end
for(y=0; y<(a-1); y++){//for3
if(y>=t){//if3
e=t;
k=Array[(y+1)][e];
for(e=0; e<b; e++){//for4
Array[(y+1)][e]=(-1)*k*Array[i][e]+Array[(y+1)][e];
}}//for3-4end
printf("\n");
}//if3end
printf("Iterasyon sonucu;\n");
for(i=0; i<a; i++)
for(j=0; j<b; j++){
printf("%f\t",Array[i][j]);
if(j==(b-1)){
printf("\n");}
}
printf("\n\n\n");
}//elseend
}//if1end
}//for1end
printf("ESELON FORM SONUCU;\n");
for(i=0; i<a; i++)
for(e=0; e<b; e++){//for
j=e;
printf("%.3f\t",Array[i][e]);
if(e==(b-1)){//if
printf("\n");}//ifend
}//forend
}//fonksiyonend
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